Steel Authority of India Limited (SAIL) has released an employment notification calling out aspirants to apply for the post of Junior Staff Nurse Trainee. Those interested can check out the eligibility, salary scale, how to apply and the complete details of the government job here.
Applicants will be selected on the basis of a written test and a skill test. The application fee is INR 250 and can be paid through net banking. Selected candidates can earn up to INR 24,110 per month. The last date to apply for this government job is Dec 26, 2018.
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SAIL Recruitment 2018 Vacancy Details
CRITERIA | DETAILS |
Name Of The Posts | Junior Staff Nurse Trainee |
Organisation | Steel Authority of India Limited |
Educational Qualification | BSc Nursing |
Experience | Freshers can apply |
Skills Required | Clinical judgement and nursing skills |
Job Location | Bokaro (Jharkhand) |
Salary Scale | INR 16,800 to INR 24,110 per month |
Industry | Steel |
Application Start Date | December 5, 2018 |
Application End Date | December 26, 2018 |
- Maximum Age Limit: 28 years
Also Read: WCR, Indian Railways Recruitment 2018 For Medical Practitioners And Dental Surgeons
How To Apply For SAIL Recruitment 2018
In order to apply for SAIL Recruitment 2018, follow these steps:
Step 1: Log on to the SAIL official website.
Step 2: Select Job Openings.
Step 3: The list of notifications will be displayed on the screen.
Step 4: Click the link that reads, JR. STAFF NURSE TRAINEE.
Step 5: Click Apply Now.
Step 6: Read the terms and conditions and click I Agree.
Step 7: The registration form will open. Enter your details in the fields provided.
Step 8: Upload the relevant documents.
Step 9: Read the declaration and click the check box to agree.
Step 10: Click Save and complete the registration process.
Follow the link - https://www.sailcareers.com/media/uploads/Web_Advt_-_PARA-Medical_-_05_12_2018_final_upload.pdf to read the detailed official notification.