Joint Entrance Examination (JEE) Main 2014 online application forms are available from today i.e 15 Nov 2013.
CBSE is set to conduct the JEE Main 2014 examination all over the world. There is no printed application form for JEE 2014 examination.
Now, candidates must have to know the normalisation procedure of marks of class 12 / qualifying marks and JEE Main 2014 score to get the all India rank.
Many students were curious about "How the board will consider the class 12 and JEE Main scores in preparing all India rank list".
Go through the below steps for the detailed normalisation procedure for JEE Main 2014 exam:
For example, lets note down the aggregate marks (Ao) obtained by each student in JEE Main exam.
Compute the percentile (P) of each student on the basis of aggregate marks in his/her own board (Bo) computed from the list of five subjects specified (each marked out of 100).
The percentile is to be computed among all students of the board whose subject combinations meet the eligibility criteria of JEE-Main.
The variable Bo is only a base for calculating percentile (P), which is further used to get corresponding JEE (Main) marks.
Determine the JEE- Main aggregate marks corresponding to percentile (P) at the All- India level. Regard this as B1.
Also, determine the JEE- Main aggregate marks corresponding to percentile (P) among the set of aggregate scores obtained in the JEE-Main by the students of that board. Regard this as B2.
The normalised board score of the candidate was computed as:
B(final) = 0.5 * (B1 + B2)
For the purpose of admission to CFTIs where it has been decided to use the JEE Mains performance and the normalised board performance in the 60:40 ratio, the composite score for drawing the merit list was computed as:
C = 0.6 * Ao + 0.4 * B(final )
Five subjects to be used for normalisation:
3. Any one of the subjects Chemistry, Biology, Biotechnology and Technical Vocational subject
4. One language
5. Any subject other than the above four subjects.